Y=-16x^2+72x+88

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Solution for Y=-16x^2+72x+88 equation:



=-16Y^2+72Y+88
We move all terms to the left:
-(-16Y^2+72Y+88)=0
We get rid of parentheses
16Y^2-72Y-88=0
a = 16; b = -72; c = -88;
Δ = b2-4ac
Δ = -722-4·16·(-88)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-104}{2*16}=\frac{-32}{32} =-1 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+104}{2*16}=\frac{176}{32} =5+1/2 $

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